x^2+5x-4=10

Solution for x^2+5x-4=10 equation:

Simplifying
x2 + 5x + -4 = 10

Reorder the terms:
-4 + 5x + x2 = 10

Solving
-4 + 5x + x2 = 10

Solving for variable 'x'.

Reorder the terms:
-4 + -10 + 5x + x2 = 10 + -10

Combine like terms: -4 + -10 = -14
-14 + 5x + x2 = 10 + -10

Combine like terms: 10 + -10 = 0
-14 + 5x + x2 = 0

Factor a trinomial.
(-7 + -1x)(2 + -1x) = 0

Subproblem 1
Set the factor '(-7 + -1x)' equal to zero and attempt to solve:

Simplifying
-7 + -1x = 0

Solving
-7 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + -1x = 0 + 7

Combine like terms: -7 + 7 = 0
0 + -1x = 0 + 7
-1x = 0 + 7

Combine like terms: 0 + 7 = 7
-1x = 7

Divide each side by '-1'.
x = -7

Simplifying
x = -7
Subproblem 2
Set the factor '(2 + -1x)' equal to zero and attempt to solve:

Simplifying
2 + -1x = 0

Solving
2 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1x = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1x = 0 + -2
-1x = 0 + -2

Combine like terms: 0 + -2 = -2
-1x = -2

Divide each side by '-1'.
x = 2

Simplifying
x = 2
Solution
x = {-7, 2}